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Two H atoms in the ground state collide ...

Two H atoms in the ground state collide in elastically. The maximum amount by which their combined kinetic energy is reduced is

A

10.20eV

B

20.40eV

C

13.6eV

D

27.2eV

Text Solution

Verified by Experts

The correct Answer is:
A
Total energy of two H-atom in ground state `=2(-13.6)= --27.2eV`. The maximum amount by which their combined kinetic energy is reduced when any one H-atom goes into first excited state after the inelastic collision that is the total energy of two H-atom after inelastic collision:
`E= (13.6)/(n^(2)) + 13.6`
`(13.6)/(2^(2))+ 13.61` [for excited state (n=2]
`=3.4 +13.6= 17.0eV`
So that hte loss in kinetic energy due to inelastic collision will be `=27.2- 7.0= 10.2eV`
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