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In the circuit shown in figure, if the A...

In the circuit shown in figure, if the A diode forward voltage drop is 0.3 V, the voltage difference between A and B is

A

1.3 V

B

2.3 V

C

0 V

D

0.5 V

Text Solution

Verified by Experts

The correct Answer is:
B
In the middle right of the circuit the capacitor behaves like an open circuit for dc 0.2 mA current will flow from A to B only. Let potential across A and B is V, so by Kirchhoff.s loop law,
`V_(AB) = (5,000 xx 0.2 xx 10^(-3)) + 0.3 + 5,000 xx 0.2 xx 10^(-3)`
`V_(AB) = 1V + 0.3 V + 1 V`
`V_(AB) = 2.3 V`
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