Read the given passage and answer the following questions.
A dry pellet of a common base B when kept in open absorbs moisture and turns sticky. The compound is also a by-product of chloro-alkali process.
When aqueous sodium carbonate `(Na_(2)CO_(3))` reacts with HCl (aq), it gives

Options

A. `NaOH, H_(2) and CO_(2)`
B. `NaCl, H_(2)O and CO_(2)`
C. `NaHCO_(3), H_(2) and CO_(2)`
D. `NaHCO_(3), H_(2)O and CO_(2)`

Explanation

To solve the question, we need to determine the products formed when aqueous sodium carbonate (Na₂CO₃) reacts with hydrochloric acid (HCl).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are sodium carbonate (Na₂CO₃) and hydrochloric acid (HCl).

2. **Understand the Reaction Type**:
- This is an acid-base reaction where a metal carbonate reacts with an acid.

3. **Write the General Reaction**:
- The general reaction for a metal carbonate reacting with an acid can be represented as:
\[ \text{Metal Carbonate} + \text{Acid} \rightarrow \text{Salt} + \text{Carbon Dioxide} + \text{Water} \]

4. **Identify the Products**:
- From the reaction of sodium carbonate with hydrochloric acid, the products will be:
- Sodium chloride (NaCl) - the salt formed from sodium and chloride ions.
- Carbon dioxide (CO₂) - released as a gas.
- Water (H₂O) - formed as a by-product.

5. **Write the Balanced Chemical Equation**:
- The balanced chemical equation for the reaction is:
\[ \text{Na}_2\text{CO}_3 (aq) + 2 \text{HCl} (aq) \rightarrow 2 \text{NaCl} (aq) + \text{CO}_2 (g) + \text{H}_2\text{O} (l) \]

6. **Conclusion**:
- Therefore, when aqueous sodium carbonate reacts with hydrochloric acid, the products formed are sodium chloride (NaCl), carbon dioxide (CO₂), and water (H₂O).

### Final Answer:
When aqueous sodium carbonate (Na₂CO₃) reacts with hydrochloric acid (HCl), it gives sodium chloride (NaCl), carbon dioxide (CO₂), and water (H₂O).

---