Identify the reducing agent in the following reactions
`4NH_(3) +5O_(2) to 4NO + 6H_(2)O`

Explanation

To identify the reducing agent in the reaction \(4NH_3 + 5O_2 \rightarrow 4NO + 6H_2O\), we will follow these steps:

### Step 1: Write down the oxidation states of all elements in the reactants and products.
- In \(NH_3\) (ammonia), nitrogen (N) has an oxidation state of -3, and hydrogen (H) has an oxidation state of +1.
- In \(O_2\) (oxygen gas), oxygen (O) has an oxidation state of 0.
- In \(NO\) (nitric oxide), nitrogen (N) has an oxidation state of +2, and oxygen (O) has an oxidation state of -2.
- In \(H_2O\) (water), hydrogen (H) has an oxidation state of +1, and oxygen (O) has an oxidation state of -2.

...