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The value of ((0.13)^2+(0.21)^2)/((0.39)...

The value of `((0.13)^2+(0.21)^2)/((0.39)^2+81(0.07)^2) div((2.4)^4+3xx(11.52)+9)/((2.4)^6+6(2.4)^4+3xx(17.28))` lies between `:`

A

0.5 and 0.6

B

0.4 and 0.5

C

0.6 and 0.7

D

0.7 and 0.8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given expression step by step, we will break it down into manageable parts and simplify each component before performing the final division. ### Step 1: Simplify the Numerator We start with the numerator of the first fraction: \[ (0.13)^2 + (0.21)^2 \] Calculating each term: \[ (0.13)^2 = 0.0169 \quad \text{and} \quad (0.21)^2 = 0.0441 \] Adding these together: \[ 0.0169 + 0.0441 = 0.061 \]
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Knowledge Check

  • The value of (3.24xx4)/(0.2)=?

    A
    `(324)/(25)`
    B
    `(162)/(25)`
    C
    `(162)/(5)`
    D
    `(324)/(5)`

  • The value of (3.24 xx 4)/(0.2) =?

    A
    `(324)/(25)`
    B
    `(162)/(25)`
    C
    `(162)/(5)`
    D
    `(324)/(5)`

  • What is the value of ((0.4)^(3)+(0.6)^(3))/([(0.4)^(2)+(0.6)^(2)-(0.4)xx(0.6)] ?

    A
    a)`1.2`
    B
    b)`1.1`
    C
    c)`1.0`
    D
    d)`0.9`

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