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A person rows a distance of 3 ( 3)/(4) k...

A person rows a distance of `3 ( 3)/(4)` km upstream in `1(1)/(2)` hours and a distance of 13 km downstream in 2 hours. How much time ( in hours) will the person take to row a distance of 90 km in still water ?

A

15

B

24

C

18

D

20

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first define the variables and then use the given information to set up equations based on the upstream and downstream rowing. ### Step 1: Define Variables Let: - \( x \) = speed of the person in still water (in km/h) - \( y \) = speed of the river flow (in km/h) ### Step 2: Convert Mixed Numbers to Improper Fractions The distances and times given in the problem need to be converted for easier calculations: - Upstream distance: \( 3 \frac{3}{4} \) km = \( \frac{15}{4} \) km - Upstream time: \( 1 \frac{1}{2} \) hours = \( \frac{3}{2} \) hours - Downstream distance: 13 km - Downstream time: 2 hours ### Step 3: Set Up Equations Using the formula \( \text{Distance} = \text{Speed} \times \text{Time} \): **For Upstream:** The effective speed upstream is \( x - y \). \[ \frac{15}{4} = (x - y) \times \frac{3}{2} \] Rearranging gives: \[ x - y = \frac{15/4}{3/2} = \frac{15}{4} \times \frac{2}{3} = \frac{30}{12} = \frac{5}{2} \] So, we have our first equation: \[ x - y = 2.5 \quad \text{(Equation 1)} \] **For Downstream:** The effective speed downstream is \( x + y \). \[ 13 = (x + y) \times 2 \] Rearranging gives: \[ x + y = \frac{13}{2} = 6.5 \quad \text{(Equation 2)} \] ### Step 4: Solve the Equations Now we have a system of equations: 1. \( x - y = 2.5 \) 2. \( x + y = 6.5 \) Adding both equations: \[ (x - y) + (x + y) = 2.5 + 6.5 \] This simplifies to: \[ 2x = 9 \implies x = 4.5 \] Now substitute \( x \) back into Equation 1: \[ 4.5 - y = 2.5 \implies y = 4.5 - 2.5 = 2 \] ### Step 5: Calculate Time to Row 90 km in Still Water Now that we have \( x = 4.5 \) km/h (the speed in still water), we can find the time taken to row 90 km: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{90}{4.5} = 20 \text{ hours} \] ### Final Answer The person will take **20 hours** to row a distance of 90 km in still water. ---
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