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In DeltaABC, angle BCA = 90^@, AC = 24 c...

In `DeltaABC, angle BCA = 90^@, AC = 24 cm and BC = 10 cm`. What is the radius (in cm) of the circum-circle of `DeltaABC`?

A

12.5

B

13

C

25

D

26

Text Solution

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The correct Answer is:
B
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