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Vijay is 10% more efficient than Vikas. ...

Vijay is 10% more efficient than Vikas. If Vikas can complete a piece of work in 33 days. Then Vijay can complete the same work in how many days ?

A

25

B

27

C

30

D

36

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the efficiencies of Vijay and Vikas, and then calculate the time taken by Vijay to complete the same work. ### Step 1: Understand the relationship between Vijay and Vikas's efficiencies. Vijay is 10% more efficient than Vikas. If we assume Vikas's efficiency is 100 units of work per day, then Vijay's efficiency can be calculated as: \[ \text{Vijay's Efficiency} = \text{Vikas's Efficiency} + 10\% \text{ of Vikas's Efficiency} \] \[ \text{Vijay's Efficiency} = 100 + 10 = 110 \text{ units of work per day} \] ### Step 2: Calculate Vikas's efficiency. Since Vikas can complete the work in 33 days, we can calculate the total work done by Vikas: \[ \text{Total Work} = \text{Vikas's Efficiency} \times \text{Time taken by Vikas} \] \[ \text{Total Work} = 100 \times 33 = 3300 \text{ units of work} \] ### Step 3: Calculate the time taken by Vijay to complete the same work. Now, we will use Vijay's efficiency to find out how many days he will take to complete the same total work: \[ \text{Time taken by Vijay} = \frac{\text{Total Work}}{\text{Vijay's Efficiency}} \] \[ \text{Time taken by Vijay} = \frac{3300}{110} = 30 \text{ days} \] ### Final Answer: Vijay can complete the same work in **30 days**. ---
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