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Express (2+3i)/(2-i) in the form a+ib...

Express `(2+3i)/(2-i)` in the form a+ib

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Here, we multiply the denominator of `(2+3i)/(2-i)`i.e.(2-i) by its conjugate complex number (2+i). Then we get,
`(2+3i)/(2-i)=((2+3i)(2+i))/((2-i)(2+i))=(4+2i+6i+3i^2)/(2^2-i^2)=(4+2i+6i-3)/(4+1)=(1+8i)/5=1/5+I(8)/5` Which is of the form A+iB.
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