Show that, `((cos2theta+isin2theta)^3(cos3theta-isin3theta)^4)/((cos3theta+isin3theta)^2(cos4theta+isin4theta)^(-3))=1`

Explanation

To show that

\[ \frac{(\cos 2\theta + i \sin 2\theta)^3 (\cos 3\theta - i \sin 3\theta)^4}{(\cos 3\theta + i \sin 3\theta)^2 (\cos 4\theta + i \sin 4\theta)^{-3}} = 1 \]

we will use Euler's formula, which states that \( e^{i\theta} = \cos \theta + i \sin \theta \).

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