`(sinA+sin3A)/(cosA+cos3A)=tan2A`

(sin A+sin3A)/(cos A+cos3A)=tan2A

Prove that: (sin5A-sin3A)/(cos5A+cos3A)=tan A(sin A+sin3A)/(cos A+cos3A)=tan2A

Prove that (sin5A-sin3A)/(cos5A+cos3A)=tan A

Prove that (sinA + sinB)/(cosA + cosB)= tan((A+B)/2)

Prove that: (sin2A sin3A-sin4A sin5A+sin3A sin6A)/(cos2A cos3A-cos4A cos5A+cos3A cos6A)=tan A tan4A

Prove that: (sin7A-2sin4A+sinA)/(cos7A-2cos4A+cosA)=tan4A

Prove that: (1+sinA-cosA)/(1+sinA+cosA)=tanA/2

Prove that: (sinA - 2sin^(3)A)/(2 cos^(3)A - cosA) = tan A

(sinA + sin3A) / (cosA + cos3A) = tanalpha, (cosA-cos2A) / (sinA + sin2A) = tanbeta, (sinA + sin3A + sin5A + sin7A) / (cosA + cos3A + cos5A + cos7A) = tan gamma , (cosA-cos5A-cos9A + cos13A) / (sinA-sin5A + sin9A-sin13A) = tandelta, then (a) alpha = 4beta (b) gamma = 2alpha (c) gamma = delta (d) none

Prove that a) (sin3A + sinA)sinA+(cos3A-cosA) cosA=0 b) cos20^(@)cos40^(@)cos80^(@)=1/8 c) (sin8thetacostheta-sin6thetacos3theta)/(cos2thetacostheta-sin3thetasin4theta) = tan2theta