Solve for `theta,(0^@ le theta le 360^@) 2sin^2theta+3 costheta=0`

Explanation

To solve the equation \(2\sin^2\theta + 3\cos\theta = 0\) for \(\theta\) in the range \(0^\circ \leq \theta \leq 360^\circ\), we can follow these steps:

### Step 1: Convert \(\sin^2\theta\) to \(\cos\theta\)

We know from the Pythagorean identity that:
\[ \sin^2\theta + \cos^2\theta = 1 \]
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