Convert Cartesian coordinate into polar coordinate
`(-1, sqrt3)`

Explanation

Here the Cartesian coordinate of the point `(x,y)=(-1, sqrt3)`
`therefore x=-1, y=sqrt3`
`therefore r^2=x^2+y^2`
`implies r^2=(-1)^2+(sqrt3)^2=4`
`implies r=2`
Also, `tantheta=-sqrt3/1 = -"tan"pi/3=tan(pi-pi/3)`
Since the point is in the second quadrant
`therefore theta=(2pi)/3`
Here the polar coordinate of the point is `(2, (2pi)/3)`