Find the equation of the line cutting off an intercept of length 2 from the negative direction of the axis of y and making an angle of `120^@` with the positive direction of X-axis.

Explanation

Here `m=tan120^@=tan(90^@+30^@)=-cot30^@=-sqrt3` and c=-2, because the intercept is cut on the negative side of Y-axis.
From the slope intercept form the equation of the line is given by `y=-sqrt3x+(-2)` or `y+sqrt3x+2=0`