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Find the equation of the line which pass...

Find the equation of the line which passes through (-1,1) and (2,-4).

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Here the points `(x_1,y_1) and (x_2,y_2)` are (-1,1) and (2,-4). Therefore the equation of the line passing through the given points is given by
`y-1=(-4-1)/(2-(-1))(x-(-1))`
5x+3y=-2
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MAHAVEER PUBLICATION-STRAIGHT LINE-QUESTION BANK
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