Find the equation of the circle with center `(1/2,1/3)` and radius `1/6`.

Explanation

To find the equation of the circle with center \((\frac{1}{2}, \frac{1}{3})\) and radius \(\frac{1}{6}\), we can use the standard form of the equation of a circle, which is given by:

\[ (x - a)^2 + (y - b)^2 = r^2 \]

where \((a, b)\) is the center of the circle and \(r\) is the radius.

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