Find the equation of the tangenet to each circle at the point specified, Circle `x^2+y^2-2x-4y-20=0` , point (4,-2)

Explanation

To find the equation of the tangent to the circle at the specified point (4, -2), we will follow these steps:

### Step 1: Rewrite the Circle's Equation
The given equation of the circle is:
\[ x^2 + y^2 - 2x - 4y - 20 = 0 \]

We can rewrite this in standard form by completing the square.

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