Find the equation of the tangenet to each circle at the point specified, Circle `x^2+y^2+4x+2y-20=0` , point (1,3)

Explanation

To find the equation of the tangent to the circle given by the equation \(x^2 + y^2 + 4x + 2y - 20 = 0\) at the point (1, 3), we will follow these steps:

### Step 1: Rewrite the Circle Equation
We can rewrite the circle equation in standard form by completing the square.

1. Start with the original equation:
\[
x^2 + y^2 + 4x + 2y - 20 = 0
...