Find the equation of the tangenet to each circle at the point specified, Circle `x^2+y^2-6x+4y-87=0` , point (-3,-10)

Explanation

To find the equation of the tangent to the circle given by the equation \( x^2 + y^2 - 6x + 4y - 87 = 0 \) at the point (-3, -10), we can follow these steps:

### Step 1: Rewrite the Circle Equation
First, we rewrite the circle equation in standard form. We can complete the square for both \( x \) and \( y \).

The equation is:
\[
x^2 - 6x + y^2 + 4y - 87 = 0
...