If the circles `x^2+y^2+2x-8y+8=0` and `x^2+y^2+10x-2y+22=0` touch each other find their point of contact

Explanation

To find the point of contact of the circles given by the equations \(x^2 + y^2 + 2x - 8y + 8 = 0\) and \(x^2 + y^2 + 10x - 2y + 22 = 0\), we will follow these steps:

### Step 1: Rewrite the Circle Equations
First, we will rewrite the equations of the circles in standard form.

1. **First Circle:**
\[
x^2 + y^2 + 2x - 8y + 8 = 0
...