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Find the vertex, focus, length of the latus rectum , equation of directrix of the parabola `3y^2=5x`.

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To solve the problem of finding the vertex, focus, length of the latus rectum, and the equation of the directrix of the parabola given by the equation \(3y^2 = 5x\), we will follow these steps: ### Step 1: Rewrite the equation in standard form The given equation is \(3y^2 = 5x\). We can rewrite this in the standard form of a parabola. To do this, we divide both sides by 3: \[ y^2 = \frac{5}{3}x ...
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MAHAVEER PUBLICATION-CO-ORDINATE GEOMETRY OF TWO DIMENSIONS (CONIC SECTION)-QUESTION BANK
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  2. The equation of the ellipse whose vertices are (+- 5, 0) and foci at (...

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  3. Find the equation of the ellipse in the following case: ends of maj...

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  4. Find the equation of the ellipse having, length of major axis 26 and f...

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  5. Find the coordinates of the foci and the vertices, the eccentricity a...

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  8. Find the equations of the hyperbola satisfying the given conditions :...

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  11. Find the eccentricity and length of the latus rectum of the ellipse x^...

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  12. What are the lengths of major axis and minor of the ellipse 9x^2+16y^2...

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  16. Find the equation of the parabola with focus at (1,-3) and the directr...

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  17. Find the co-ordinate of focus and the equation of the directrix of the...

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  18. Find the vertex, focus, length of the latus rectum , equation of direc...

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  19. If the eccentricities of the ellipses x^2/alpha^2 +| y^2/beta^2=1 and ...

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  20. Find the length of latus rectum, equation of directrices of the ellips...

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