Find the following integral (using partial fraction method)
`int (2x+1)/((x-1)(x+2)(x-3)) dx`

Explanation

To solve the integral \( \int \frac{2x+1}{(x-1)(x+2)(x-3)} \, dx \) using the partial fraction method, we will follow these steps:

### Step 1: Set up the partial fraction decomposition
We express the integrand as a sum of simpler fractions:
\[ \frac{2x+1}{(x-1)(x+2)(x-3)} = \frac{A}{x-1} + \frac{B}{x+2} + \frac{C}{x-3} \]
where \( A \), \( B \), and \( C \) are constants that we need to determine.
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