A body moving with uniform acceleration, travels 24 m in the 6th second and 44 m in the 11th second. At the nth second, find
(i) the acceleration and
(ii) the initial velocity of the body

Explanation

To solve the problem step by step, we will use the equations of motion. The distance traveled by a body in the nth second can be expressed using the formula:

\[ S_n = u + \frac{1}{2} a (2n - 1) \]

where:
- \( S_n \) is the distance traveled in the nth second,
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
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