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A bullet moving with an initial velocity...

A bullet moving with an initial velocity of `20 m s^(-1)`, strikes a target and comes to rest after penetrating the target to a distance of 10 cm. Calculate the retardation caused by the target.

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AI Generated Solution

To solve the problem of calculating the retardation caused by the target when a bullet comes to rest after penetrating a distance of 10 cm, we can use the third equation of motion. Here’s the step-by-step solution: ### Step 1: Identify the known values - Initial velocity (U) = 20 m/s - Final velocity (V) = 0 m/s (since the bullet comes to rest) - Distance (S) = 10 cm = 0.1 m (convert cm to m) ### Step 2: Write the equation of motion ...
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Knowledge Check

  • A bullet moving with a velocity of 30sqrt(2) ms^(-1) is fired into a fixed target. It penetrated into the target to the extent of s metres. If the same bullet is fired into a target of thickness (s)/(2) metres and of the same material with the same velocity, then the bullet comes out of the target with velocity

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    B
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    C
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    D
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  • A bullet fired into a wooden block loses half of its velocity after penetrating 60cm. It comes to rest after penetrating a further distance of

    A
    22cm
    B
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    C
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    D
    26cm

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    B
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