Home
Class 9
PHYSICS
A ball 'A' is thrown upwards from ground...

A ball 'A' is thrown upwards from ground level with a velocity of `20 ms^(-1)`. Another ball 'B' is thrown downwards from a height of 40 m with the same speed. Find the height at which the two balls meet (take `g = 10 m s^(-2)`).

Text Solution

AI Generated Solution

To find the height at which the two balls meet, we can analyze the motion of both balls separately and then set their heights equal to each other. ### Step-by-step Solution: 1. **Define the Variables:** - Let the height at which the two balls meet be \( h \). - For ball A (thrown upwards): - Initial velocity \( u_A = 20 \, \text{m/s} \) ...
Promotional Banner

Topper's Solved these Questions

  • DESCRIPTION OF MOTION

    CENGAGE PHYSICS|Exercise CONSOLIDATED EXERCISE (COMPREHENSION)|7 Videos
  • DESCRIPTION OF MOTION

    CENGAGE PHYSICS|Exercise CONSOLIDATED EXERCISE (MATCH THE COLUMNS)|3 Videos
  • DESCRIPTION OF MOTION

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE (EXERCISE SET - II)|7 Videos
  • ELASTICITY

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

Similar Questions

Explore conceptually related problems

Two balls are thrown simultaneously, A vetically upwards with a speed of 20 ms^(-1) from the ground, and B vetically downwards from height of 40 m with the same speed and along the same line of motion. At what points do the two balls collide? Take g= 9.8 ms^(-2) .

Two balls are thrown simultaneously, A vertically upwards with a speed of 20 m/s from the ground, and B vertically downwards from a height of 40 m with the same speed along the same line of motion. At what point do the two balls collide? Take g = 9.8 m//s^(2) .

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown upwards from the ground with an initial speed of u. The ball is at height of 80m at two times, the time interval being 6 s. Find u. Take g=10 m//s^2.

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball is thrown vertically upward with speed 40 m//s . Simultaneously, another ball is dropped from a height 200 m in the same verticle line. When and where the balls meet?

A ball is thrown vartically upward with speed 70 m//s . After 1 s, another ball is dropped from a height 185 m in the same vertical line. When and where the balls collide?

A ball is thrown upwards with a speed u from a height h above the ground.The time taken by the ball to hit the ground is

A ball is dropped from the top of a tower. After 2 s another ball is thrown vertically downwards with a speed of 40 m//s . After how much time and at what distance below the top of tower the balls meet?