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A parachutist drops freely from an aero ...

A parachutist drops freely from an aero plane for 10 s before the parachute open out. Then he descends with a net retardation of `2.5 m s^(-2)`. If he bails out of the plane at a height of 2495 m and `g = 10 m s^(-2)`, what is his velocity on reaching the ground?

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into parts: ### Step 1: Calculate the velocity of the parachutist after free fall for 10 seconds. The formula to calculate the final velocity (v) after falling freely under gravity is given by: \[ v = u + gt \] where: - \( u = 0 \) (initial velocity, since he drops from rest), - \( g = 10 \, m/s^2 \) (acceleration due to gravity), ...
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Knowledge Check

  • A parachutist drops from an aeroplane for 10s before the parachute opens out. Then he descends with a net retardation of 2.5ms^(-2) . If he bails out of plane at a height of 2495m and g=10ms^(-2) , his velocity on reaching the ground will ve

    A
    `2.5ms^(-1)`
    B
    `7.5ms^(-1)`
    C
    `5ms^(-1)`
    D
    `10ms^(-1)`
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    A
    `5 m s^(-1)`
    B
    `10 ms^(-1)`
    C
    `15 ms^-1)`
    D
    `20 ms^(-1)`
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    `10 ms^(-1)`
    B
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    C
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    D
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