The minimum distance to stop a car is x when it is moving with a velocity v, then what will be the minimum distance to stop it in the same time when it will move with a velocity mv.

Options

A. `m^2 x`
B. `mx`
C. `x//m^2`
D. `x//m`

Answer

B

Explanation

`v^2 = u^2 + 2as`
`0^2 = v^2 - 2 xx ax`
`implies x = (v^2)/(2a) " "....(i)`
`0^2 = (mv)^2 - 2 xx ay`
`implies y = (mv^2)/(2a)`
`y = mx " "` from (i)