A ball is thrown vertically upward in air. When the particle is at a height half of its maximum height its speed is 10 m/s. Then the maximum height attained by the particle is

Options

A. 20 m
B. 15 m
C. 10 m
D. 8 m

Answer

C

Explanation

`V^2 = u^2 + 2as`
`implies (10)^2 = u^2 - 2 xx g xx H/2 " " ....(i)`
at maximum height, `v^2= 0`
`implies 0^2 = u^2 + (-2) xx g xx H " from (i)"`
`implies 100 = 2gH - gH`
`implies 100 = gH`
`implies H = 10 m`