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Speed of two identical cars are u and 4u...

Speed of two identical cars are u and 4u at the instant. The ratio of the respective distances in which the two cars are stopped from the instant is

A

`1:1`

B

`1:8`

C

`1:4`

D

`1:16`

Text Solution

Verified by Experts

The correct Answer is:
D
Car `1 : 0^2 = u^2 - 2 ax_1 implies x_1 = (u^2)/(2a)`
Car `2 : 0^2 = (4u)^2 - 2ax_2 implies x_2 = (16u^2)/(2a)`
`therefore (x_1)/(x_2) = 1/16`
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