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A block is placed on an inclined plane. ...

A block is placed on an inclined plane. The angle of inclination of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is

A

`sin theta`

B

`cos theta`

C

`cot theta`

D

`tan theta`

Text Solution

AI Generated Solution

To solve the problem of finding the coefficient of kinetic friction for a block sliding down an inclined plane at a constant speed, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Block**: When a block is placed on an inclined plane, the forces acting on it are: - The gravitational force (weight) \( Mg \) acting vertically downwards. - The normal force \( N \) acting perpendicular to the surface of the incline. ...
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Knowledge Check

  • A block has been placed on an inclined plane . The slope angle of theta of the plane is such that the block slides down the plane at a constant speed . The coefficient of kinetic friction is equal to :

    A
    sin `theta`
    B
    cos `theta`
    C
    g
    D
    tan `theta`

  • A block has been placed on an inclined plane with the slope angle theta . Block slide down the plane at constant speed. The cofficient of Kinetic friction is equal to

    A
    `sin theta`
    B
    `cos theta`
    C
    `g`
    D
    `tan theta`

  • A block of mass m is placed on a rough inclined plane. When the inclination of the plane is theta , the block just beging to slide down the plane under its own weight. The minimum force applied parallel to the plane, to move the block up the plane, is.

    A
    `mgsintheta`
    B
    `2mgsintheta`
    C
    `mgcostheta`
    D
    `mg tantheta`

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    What is the time required for a block to slide down from the top to the bottom ofan inclined plane 6.4 m long if the inclination of the plane with the horizonta l is 30° and the coefficient of friction= 0.2?

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