In the figure shown, the frictional coefficient between the table and the block is 0.2. Find the ratio of tensions in the right and the left strings.

Options

A. 0.725
B. 34:12
C. 2:3
D. 3:2

Explanation

`150-T_(2)=15a " "...(i)`
`T_(2)-T_(1)-muN=5a " " ...(ii)`
`T_(1)-50=5a " " ...(iii)`
`100-muN=25a`
`impliesa=90/25=19/5`
From(i)
`150-T_(2)=15 xx 18/5impliesT_(2)=150-54`
`T_(2)=96N`
`From(iii)`
`T_(1)-50=5aimpliesT_(1)=50+18/5=68`
`:.T_(1)/T_(2)=68/96=34/48=17/24`