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For steel surfaces, the coefficient of f...

For steel surfaces, the coefficient of friction is `mu= 0.8` and between teflon surfaces `mu= 0.04`. A steel block of mass 2 kg kept on a steel surface has a limiting frictional force f. What should be the mass of a teflon block kept on a teflon surface to have the limiting frictional force same as f? Take `g=10 m s^(-1)`.

Text Solution

Verified by Experts

`mu_(steel)=0.8`
`m_(steel)=2kg`
`mu_("teflon")=0.04.m_("teflon")=?`
Force f is same in both the cases
Limiting force in first case `=mu_(steel) xx R`
where `R=mu_(steel) xx g`
`:.mu_(steel) xx m_(steel) xx g=mu_(teflon) xx m_(teflon) xx g`
`m_(teflon)=40kg`
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