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Young's modulus of a perfectly rigid bod...

Young's modulus of a perfectly rigid body is

A

zero

B

unity

C

finite and low

D

infinite

Text Solution

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The correct Answer is:
To determine the Young's modulus of a perfectly rigid body, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Young's Modulus**: Young's modulus (Y) is defined as the ratio of stress (force per unit area) to strain (deformation per unit length) in a material. It is given by the formula: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] 2. **Defining Stress and Strain**: - **Stress** is defined as the force (F) applied per unit area (A): \[ \text{Stress} = \frac{F}{A} \] - **Strain** is defined as the change in length (ΔL) divided by the original length (L): \[ \text{Strain} = \frac{\Delta L}{L} \] 3. **Characteristics of a Perfectly Rigid Body**: A perfectly rigid body is one that does not deform under any applied load. This means that: - The change in length (ΔL) is zero when a force is applied. - Therefore, the strain (ΔL/L) is also zero. 4. **Calculating Young's Modulus for a Perfectly Rigid Body**: Since strain is zero for a perfectly rigid body, we can substitute this into the Young's modulus formula: \[ Y = \frac{\text{Stress}}{\text{Strain}} = \frac{\frac{F}{A}}{0} \] This results in a division by zero, which mathematically leads to: \[ Y = \infty \] 5. **Conclusion**: Hence, the Young's modulus of a perfectly rigid body is considered to be infinite. ### Final Answer: The Young's modulus of a perfectly rigid body is infinity. ---
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