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To double the length of an iron wire hav...

To double the length of an iron wire having area of `0.5" cm"^(2)` cross section, the required force will be [Given `(Y=10^(12)" dyne/cm"^(2))`]

A

`10xx10^(-7)N`

B

`10xx10^(7)N`

C

`0.5xx10^(-7)N`

D

`0.5xx10^(12)N`

Text Solution

Verified by Experts

The correct Answer is:
D
Strain `=(L)/(Delta)=(L)/(L)=1`
Stress `=F/ArArr(F)/(0.5)`
`Y=(F//A)/(1)rArrF=YxxA=10^(12)xx0.5`
`F=0.5xx10^(12)" dyne"`
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