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A horizontal rod suspended from two wire...

A horizontal rod suspended from two wires of same length and cross - section. Their Young's modulus are `Y_(1)` and `Y_(2)` respectively. The equivalent Young's modulus will be

A

`(Y_(1)+Y_(2))/(2)`

B

`Y_(1)+Y_(2)`

C

`2(Y_(1)+Y_(2))`

D

`(Y_(1)+Y_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
Say the equivalent Young.s modulus is Y and area of cross section be 2A.
As we know extended wires behave like springs
`[F=(AY(DeltaL))/(L)" is equivalent to "F=kx]`
For parallel combination `K_(1)+K_(2)=K_("eq")`
`rArr(AY_(1))/(L)+(AY_(2))/(L)=((2A)Y)/(L)`
`rArrY=(Y_(1)+Y_(2))/(2)`
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