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A person standing between two vertical cliff's produces a sound. Two successive echoes are heard at 4 s and 6 s. Calculate the distance between the cliffs. [The speed of sound in air = 320 m `s^(-1)`]

Text Solution

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Positions of person and cliff can be represented as shown in the figure

Distance of the nearest cliff, `d_(1)` = ?
Time taken to hear echo from this cliff, `t_(1) =4 s`
Distance of the other cliff, `d_2` = ?
Time taken to hear echo from thin cliff, `t_2 = 6 s`
`d_(1) = 640 m, d_2 = 960 m`
Distance between cliffs = `d_(1) + d_2` = 1600 m
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