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An observer standing in front of a vertical wall claps 10 times in 1 s. He adjusts his distance from the wall in such a way that the sound of his clapping coincides with the echo. This happens when his distance from the wall is 17.5 m. What is the velocity of sound?

Text Solution

Verified by Experts

Number of claps in 1 s= 10
Time interval between two claps = `(1)/(10)` = 0.1 s
Distance covered by sound, `d=2xx 17.5 = 35 m` Time taken, t = 0.1 s
`v = 350 m s^(-1)`
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