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Delta H("neutrallisation") for the react...

`Delta H_("neutrallisation")` for the reaction .
`NaOH + HCl to NaCl + H_(2)O` is 57.1 kJ/mole.
The heat released when 0.25 mole of NaOH is titrated against 0.25 mole of HCl will be

A

22.5 kJ

B

57.1 kJ

C

28.6 kJ

D

14.3 kJ

Text Solution

Verified by Experts

The correct Answer is:
D

Heat released `= nH_(2)O xx 57.1 kJ`
` = 0.25 xx 57.1 kJ`
` = 14.3 kJ`
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