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If S + O(2) to SO(2), DeltaH = - 298.2 k...

If `S + O_(2) to SO_(2), DeltaH = - 298.2 kJ`
`SO_(2) + 1//2O_(2) to SO_(3), Delta H = - 98.7 KJ`
`SO_(3) + H_(2)O to H_(2)SO_(4) , Delta H = - 130.2 kJ`
`H_(2) + 1//2 O_(2) to H_(2)O , Delta H = - 287 .3 kJ`
Then the enthalpy of formation of `H_(2)SO_(4) ` at 298 K is .

A

`-814.4 kJ`

B

`-650.3` kJ

C

`-320.5 kJ`

D

`-233.5 kJ`

Text Solution

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The correct Answer is:
A
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Given: (i) S+O_2 to SO_2, Delta H=-298.2 kJ (ii) SO_2 + 1/2 O_2 to SO_3, Delta H=-98.7 kJ (iii) SO_3 + H_2 O to H_2 SO_4, Delta H=-130.2 kJ (iv) H_2 + 1/2 O_2 to H_2 O, Delta H=-287.3 kJ , Then the enthalpy of formation of H_2 SO_4 at 298 K will be _________ .

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underline(S)O_(3)+H_(2)O to H_(2)SO_(4)

If, S+O_2 rarr SO_2, Delta H =-298.2 kj SO_2 + 1/2 O_2 rarr SO_3, Delta H=-98.7 kJ SO_3 + H_2 O rarrr H_2SO_4 , Delta H =-130.2 kJ H_2 + 1/2 O_2 rarr H_2 O, Delta H =-227.3 kJ Find Delta H for formation of H_2SO_4 at 298 K.

If {:(SO_(2)+1/2O_(2) rarr SO_(3),DeltaH = -98.7 kJ),(SO_(3)+H_2O rarr H_(2)SO_(4),DeltaH = -130.2 kJ),(H_(2)+1/2O_(2) rarr H_2O , Delta H = -287.3 kJ),(S + H_2 + 2O_(2) rarr H_2SO_4, DeltaH = -814.4 kJ):} Then enthaply of SO_(2) at 298 K is:

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