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Molecular formula of acetic acid is CH(...

Molecular formula of acetic acid is `CH_(3)COOH`. Calculate its percentage composition . [Given : Atomic masses C=12, H = 1 and O = 16].

Text Solution

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Molecular mass ` = 2 xx 12 + 4 xx 1 + 2 xx 16`
` = 24 + 4+ 32=60`
`% C = (24 xx 100)/(60) = 40`
`%H = ( 4 xx 100)/(60) = 6.66`
`%O = (32 xx 100)/(60) = 53.33`
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