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If arg (bar(z)(1))= "arg" (z(2)), (z ne...

If arg `(bar(z)_(1))= "arg" (z_(2)), (z ne 0)` then

A

`z _(2) = k z _(1) ^(-1) , ( k gt 0)`

B

`z _(2) = k z _(1), ( k gt 0)`

C

`|z_(2)| = |barz_(1)|`

D

`z _(1) = z _(2)`

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