The equation of the circle whose radius ...

The equation of the circle whose radius is `sqrt7` and concentric with the circle `x^(2)+y^(2)-8x+6y-11=0` is

A

`x^(2)+y^(2)-8x+6y+7=0`

B

`x^(2)+y^(2)-8x+6y+18=0`

C

`x^(2)+y^(2)-8x+6y-4=0`

D

`x^(2)+y^(2)-8x+6y-18=0`

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