Home
Class 12
MATHS
A and B throw a die alternately till one...

A and B throw a die alternately till one of them gets a ‘6’ and wins the game. If A stars first, then the probability of winning of A is

A

`(5)/(6)`

B

`(1)/(6)`

C

`(5)/(11)`

D

`(6)/(11)`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Two persons A and B throw a die alternatively till one of them gets a three and wins the game.If A begins,find (i) the probability of winning of A.

Two persons A and B throw a die alternatively till one of them gets a three and wins the game.If A begins,find (ii) the probability of winning of B.

A and B throw a die alternatively: till one of them gets a 6 and wins the game. Find their respective probabilities of winning, If A starts first:

Two persons A and B throw a die alternately till one of them gets a 3 and wins the game, the respectively probabilities of wining , if A begins are :

A and B toss on alternately till one of them tosses heads and wins the game, their respective probabilities of winning are : a) 1/4 and 3/4 b) 1/2 and 1/2 c) 2/3 and 1/3 d) 1/5 and 4/5

A die is thrown three times. Events A and B are defined as below: A: 4 on the third throw B: 6 on the first and 5 on the second throw, Find the probability of A given that B has already occurred.

In a lottery, a person chosen six different natural numbers from 1 to 20 and if these six number match with six numbers already fixed by the lottery committee, he wins the prize. What is the probability of winning the prize in the game (order of the numbers is not important)

In a chess tournament, assume that your probability of winning a game is 0.3 against level 1 players, 0.4 against level 2 players, and 0.5 against level 3 players. It is further assumed that among the players 50% are at level 1, 25 % are at level 2 and the remaining are at level 3. The probability of winning a game against a randomly chosen player is