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In the imaginary language, the digits 0,...

In the imaginary language, the digits 0,1,2,3,4,5,6,7,8 and 9 are substituted by a,b,c,d,e,f,g,h, I and j. And 10 is written as be.
`bee + fg - (ca xx h //be)` is equal to

A

bhc

B

bic

C

bib

D

bja

Text Solution

Verified by Experts

The correct Answer is:
D
The given expression is
`bee + fg - ( ca xx (h)/(be))`
Substituting the value sin the given expression, we get
`144 + 56 - (20 xx (7)/(14)) = 200 - (20 xx (1)/(2))`
`= 200 - 10 = 190 = bja`
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