Mahendra Singh stands on the tip of an equilateral triangle whose area is `36 sqrt3 m^2`. He goes around the three sides and returns to the same tip. Then he goes North and covers as much distance as before. He turns right and reaches point P which is parallel to tip of equilateral triangle. How far is he from original point?

Options

A. 36 m
B. 144 m
C. 72 m
D. 156 m

Answer

D

Explanation

The movements of Mahendra Singh are as shown in Fig, i.e,A to B, B to C, C to, A, A to Q and Q to P.

A = Starting point, P = End point
Given, Area of equilateral triangle ABC = `36 sqrt3 m^2`
`therefore(sqrt3)/4("side")^2`]
or, side = `6xx4=24`
Therefore, Mahendra.s distance from the starting point A
= AB + BC + CA = 72 + 72 (Northwards)
`+12(1/2 "of BC=QP")=156m`