ABCD is a parallelogam and AP and CQ are the perpendicualr form vertices A and C on diagonal

Show that: `triangleAPBequivtriangleCQD`

ABCD is a parallelogam and AP and CQ are the perpendicualr form vertices A and C on diagonal Show that: AP=CQ

ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that Delta APB ~= Delta CQD .

ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that AP = CQ.

ABCD is a parallelogram and AP and CQ are the perpendiculars from vertices A and C on its diagonal BD (See fig.) Show that AP = CQ.

In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP=BQ AP=CQ

The points A(4, 5, 10), B(2, 3, 4) and C(1, 2, -1) are three vertices of a parallelogram ABCD. Find the vector equations of side AB and BC and also find the coordinates of point D .

Let ABCD be a square of side length 2 units. C2 is the circle through vertices A, B, C, D and C1 is the circle touching all the sides of the square ABCD. L is a line through A. . If P is a point on C1 and Q in another point on C2, then (PA^2+ PB^2+ PC^2+PD^2)/ (QA^2+ QB^2+ QC^2+ QD^2) is equal to

ABCD is a parallelogram. P is any point on AD, such that AP = 1/3AD and Q is a point on BC such that CQ = 1/3BC . Prove that AQCP is a parallelogram.