Home
Class 9
MATHS
ABC is a right triangle right angled at ...


ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX `bot` DE meets BC at Y. Show that:
`triangleMBC congtriangleABD`

Promotional Banner

Topper's Solved these Questions

  • AREA OF PARALLELOGRAMS AND TRIANGLES

    MODERN PUBLICATION|Exercise EXERCISE|83 Videos

  • CIRCLES

    MODERN PUBLICATION|Exercise EXERCISE|94 Videos

Similar Questions

Explore conceptually related problems

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX bot DE meets BC at Y. Show that: triangleFCB congtriangleACE

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX bot DE meets BC at Y. Show that: ar(BYXD) =2ar(MBC)

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX bot DE meets BC at Y. Show that: ar(BYXD) = ar(ABMN)

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX bot DE meets BC at Y. Show that: ar(CYXE) = ar(ACFG)

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX bot DE meets BC at Y. Show that: ar(CYXE) = 2ar(FCB)

ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segent AX bot DE meets BC at Y. Show that: ar(BCED) = ar(ABMN) + ar (ACFG)

ABC is a triangle, right-angled at C. If AB = 25 cm and AC = 7 cm, find BC.

ABC is an isosceles triangle right angled at A. forces of magnitude 2sqrt(2),5 and 6 act along BC, CA and AB respectively. The magnitude of their resultant force is

MODERN PUBLICATION-AREA OF PARALLELOGRAMS AND TRIANGLES-EXERCISE
  1. ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squ...

    Text Solution

    |

  2. In the figure. Show that ABCD is a parallelogram. Calculate the are...

    Text Solution

    |

  3. Find the area of a rhombus whose diagonals are of lengths 10 cm and 8....

    Text Solution

    |

  4. Calculate the area of trap. PQRS, given in the figure.

    Text Solution

    |

  5. In the figure. ABCD in a trapezium in which AB||DC. Proe that ar(trian...

    Text Solution

    |

  6. In a quad. ABCD it is given that BD = 16 cm. If AL bot BD and CM bot B...

    Text Solution

    |

  7. ABCD is a parallelogram whose diagonals intersect at E. AC is produced...

    Text Solution

    |

  8. ABCD is a parallelogram whose diagonals intersect at E. AC is produced...

    Text Solution

    |

  9. P and Q are respectively the midpoints of sides AB and BC or a triangl...

    Text Solution

    |

  10. P and Q are respectively the midpoints of sides AB and BC or a triangl...

    Text Solution

    |

  11. P and Q are respectively the midpoints of sides AB and BC or a triangl...

    Text Solution

    |

  12. In fig. ABCD and AEFG are two parallelograms. If angleC=55^@ and deter...

    Text Solution

    |

  13. ABCD and AEFD are two parallelograms Prove that: ar(triangleAPE) : a...

    Text Solution

    |

  14. In Fig. ABCD is a parallelogram. Prove that ar (DeltaACP) = ar (Del...

    Text Solution

    |

  15. In triangleABC, it L and M are points on AB and AC respectively such t...

    Text Solution

    |

  16. In triangleABC, it L and M are points on AB and AC respectively such t...

    Text Solution

    |

  17. D and E are points on sides AB and AC respectively of DeltaABC such th...

    Text Solution

    |

  18. D and E are points on sides AB and AC respectively of DeltaABC such th...

    Text Solution

    |

  19. ABCD is parallelogram. X and Y are the mid-points of BC and CD respect...

    Text Solution

    |

  20. PQRS and PABC are two parallelograms of equal area. Prove that QC||BR

    Text Solution

    |

  21. Two parallelograms ABCD and AEFB are drawn on opposite sides of AB. Pr...

    Text Solution

    |