Home
Class 9
MATHS
If D, E and F are three points on the si...

If D, E and F are three points on the sides BC, CA and AB, respectively, of a triangle ABC such that the lines AD, BE and CF are concurrent, then show that
`" "(BD)/(CD)*(CE)/(AE)*(AF)/(BF)=1`

Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    MODERN PUBLICATION|Exercise EXERCISE|94 Videos
  • AREA OF PARALLELOGRAMS AND TRIANGLES

    MODERN PUBLICATION|Exercise EXERCISE|83 Videos
  • CONSTRUCTIONS

    MODERN PUBLICATION|Exercise EXERCISE|69 Videos

Similar Questions

Explore conceptually related problems

If D,E and F are the mid-points of the sides BC,CA and AB, respectively of a DeltaABC and O is any point, show that (i) AD+BE+CF=0

D,E and F are mid-points of the sides BC, CA and AB respectively of triangleABC . Prove that ar(triangleDEF) = 1/4 ar (triangleABC)

D,E and F are the middle points of the sides of the triangle ABC, then

Points P, Q and R lie on sides BC, CA and AB respectively of triangle ABC such that PQ || AB and QR || BC, prove that RP II CA.

D,E and F are mid-points of the sides BC, CA and AB respectively of triangleABC . Prove that ar(||gmBDEF)= 1/2 ar (triangleABC)

D, E and F are respectively the mid-points of the sides BC, CA and AB of a triangle ABC . Show that:- BDEF is a parallelogram.

D and E are points on the sides CA and CB respectively of a triangle ABC right angled at C. Prove that AE^2+BD^2=AB^2+DE^2 .

D,E,F are the middle points of the sides [BC],[CA],[AB] respectively of a triangle ABC. Show that : FE is parallel to BC and half of its length.

E and F are the mid points of non-parallel sides AD and BC respectively of a trapezium prove that EF||AB.

In the fig D,E and F are the mid points of the sides BC,CA and AB respectively of triangleABC . If BE and DF intersect at X while CF and DE ntersect at Y. prove that XY=1/4BC

MODERN PUBLICATION-CIRCLES-EXERCISE
  1. If D, E and F are three points on the sides BC, CA and AB, respectivel...

    Text Solution

    |

  2. The radius of a circle is 8 cm and the length of its chords is 12 cm. ...

    Text Solution

    |

  3. Find the length of a chord which is at a distance of 24 cm from the ce...

    Text Solution

    |

  4. A chord of length 16 cm is drawn in a circle of radius 10 cm. Find the...

    Text Solution

    |

  5. Find the length of a chord which is at a distance of 24 cm from the ce...

    Text Solution

    |

  6. PQ and RS are two parallel chords of a circle whose centre is O and ra...

    Text Solution

    |

  7. PQ and RS are two parallel chords of a circle whose centre is O and ra...

    Text Solution

    |

  8. AB and CD are two chords of a circle such that AB = 6 cm, CD = 12 cm a...

    Text Solution

    |

  9. Two parallel chords of lengths 30 cm and 16 cm are drawn on the opposi...

    Text Solution

    |

  10. In an equilateral triangle, prove that centroid and circumcentre coinc...

    Text Solution

    |

  11. Two chords PQ and RS of a circle are parallel to each other and AB is ...

    Text Solution

    |

  12. In fig., two circles with centres O, O' touch externally at a point A....

    Text Solution

    |

  13. Prove that the right-bisector of a chord of a circle bisects the corre...

    Text Solution

    |

  14. Two chords AB and AC of a circle are equal. Prove that the centre of t...

    Text Solution

    |

  15. Two equal chords AB and CD of a circle C(O,r) when produced meet at a ...

    Text Solution

    |

  16. Two equal chords AB and CD of a circle C(O,r) when produced meet at a ...

    Text Solution

    |

  17. If a diameter of a cirlce bisects each of the chords of the circle, pr...

    Text Solution

    |

  18. Prove that the perpendicular at the point of contact to the tangent to...

    Text Solution

    |

  19. Diameter is the largest chord of the circle. (True/False)

    Text Solution

    |

  20. PQ and RQ are chords of a circle equidistant from the centre. Prove th...

    Text Solution

    |

  21. In given Fig. , AD = AE and D and E are points on BC, such that BD = ...

    Text Solution

    |