A rectangular sheet of paper `30cmx×18cm` can be transformed into the curved surface of a right circular cylinder in two ways namely, either by rolling the paper along its length or by rolling it along its breadth. Find the ratio of the volumes of the two cylinders, thus formed.

A rectangular sheet of paper of dimensions 30 cmxx16 cm can be transformed into an open ended cylinder in two ways. Find the ratio of volumes of two cylinders thus formed.

Fill in the blanks. A rectangle of length 44 cm is rolled along its length to form a cylinder then the radius of the cylinder is ________ .

The diameter of the base of a right circular cylinder is 28 cm and its height is 21 cm. Find its curved surface area

The ratio of the curved surface area and the total surface area of a circular cylinder is 1:2 and the total surface area is 616cm^2 . Find its volume.

Two steel sheets each of length a_1 and breadth a_2 are used to prepare the surfaces of two right circular cylinders-one having volume v_1 and height a_2 and other having volume v_2 and height a_1 then

The lateral surface area of a hollow cylinder is 4224 cm^2 . It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?

A right circular cylinder of length L (in m) and of radius R (in m) has its center at the origin and its length along the X-axis. A uniform electric field vecE = E_x hat I N C^-1 for x > 0 and vec E = -E_xhati NC^-1 for x < 0 exists over the cylinder. Find the net charge enclosed by the cylinder.