The unit cell of metallic silver is fcc. If radius of Ag atom is 144.4 pm, calculate
edge length of unit cell

Explanation

For fee unit cell, r = 0.3535 a
r = 144.4 pm= `144.4 xx 10^(-12)`m
= `144.4 xx 10^(-10)` cm
a = `r/(0.3535) = (144.4 xx 10^(-10)cm)/0.3535`
= `4.085 xx 10^(-3)` cm